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Sample code for Listing file names in a directory

September 25, 2008 by Krishna Srinivasan Leave a Comment

also read:

  • Java Tutorials
  • Java EE Tutorials
  • Design Patterns Tutorials
  • Java File IO Tutorials

[code lang=”java”]
public String[] getFileNames(String DirPath) {
String directoryName;
File directory;
String[] files;
directory = new File(DirPath);
if (directory.isDirectory() == false) {
if (directory.exists() == false) {
System.out.println("There is no such directory!");
return null;
} else {
System.out.println("That file is not a directory.");
return null;
}
} else {
files = directory.list();
// System.out.println("Files in directory -" + directory + "/:");
for (int i = 0; i < files.length; i++) {
//System.out.println("" + files[i]);
}
return files;
}
}
[/code]

Filed Under: Java Tagged With: Core Java

About Krishna Srinivasan

He is Founder and Chief Editor of JavaBeat. He has more than 8+ years of experience on developing Web applications. He writes about Spring, DOJO, JSF, Hibernate and many other emerging technologies in this blog.

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